pythonregex

Lord of The Rings

Ben Gorman

Ben Gorman

Life's a garden. Dig it.

Here's a quote from The Lord of the Rings: The Fellowship of the Ring :material-sword: :material-bow-arrow: :material-axe-battle:.

quote = "Aragorn: If by my life or death I can protect you I will. You have my sword. Legolas: And you have my bow. Gimli: And my ax."

Build a list of the weapons that have been offered to Frodo.

Expected result

weapons = ['sword', 'bow', 'ax']

Regex Functions

Function Description Return Value
re.findall(pattern, string, flags=0) Find all non-overlapping occurrences of pattern in string list of strings, or list of tuples if > 1 capture group
re.finditer(pattern, string, flags=0) Find all non-overlapping occurrences of pattern in string iterator yielding match objects
re.search(pattern, string, flags=0) Find first occurrence of pattern in string match object or None
re.split(pattern, string, maxsplit=0, flags=0) Split string by occurrences of pattern list of strings
re.sub(pattern, repl, string, count=0, flags=0) Replace pattern with repl new string with the replacement(s)

Regex Patterns

Pattern Description
[abc] a or b or c
[^abc] not (a or b or c)
[a-z] a or b ... or y or z
[1-9] 1 or 2 ... or 8 or 9
\d digits [0-9]
\D non-digits [^0-9]
\s whitespace [ \t\n\r\f\v]
\S non-whitespace [^ \t\n\r\f\v]
\w alphanumeric [a-zA-Z0-9_]
\W non-alphanumeric [^a-zA-Z0-9_]
. any character
x* zero or more repetitions of x
x+ one or more repetitions of x
x? zero or one repetitions of x
{m} m repetitions
{m,n} m to n repetitions
{m,n} m to n repetitions
\\, \., \* backslash, period, asterisk
\b word boundary
^hello starts with hello
bye$ ends with bye
(...) capture group
(po|go) po or go

Solution

This content is gated

Subscribe to one of the products below to gain access