Here's a quote from The Matrix :material-matrix:
quote = """The title bar reads: "Combat Series 10 of 12," file \n categories flashing beneath it: Savate, Jujitsu, Ken Po, \n Drunken Boxing..."""
Let Tank, Neo's instructor, get a list of martial arts Neo has learnt.
expected = [ 'Savate' , 'Jujitsu' , 'Ken Po' , 'Drunken Boxing' ]
Note these are strings between commas after the word "categories" and the next colon. Try to accomplish the task with a single regex pattern that would match all occurrences in the string.
Mind that you will need the PyPi regex to achieve this. Make sure you install it by running pip install regex pip3 install regex
Function
Description
Return Value
re.findall(pattern, string, flags=0) Find all non-overlapping occurrences of pattern in string
list of strings, or list of tuples if > 1 capture group
re.finditer(pattern, string, flags=0) Find all non-overlapping occurrences of pattern in string
iterator yielding match objects
re.search(pattern, string, flags=0) Find first occurrence of pattern in string
match object or None
re.split(pattern, string, maxsplit=0, flags=0) Split string by occurrences of pattern
list of strings
re.sub(pattern, repl, string, count=0, flags=0) Replace pattern with repl
new string with the replacement(s)
Pattern
Description
[abc] a or b or c
[^abc] not (a or b or c )
[a-z] a or b ... or y or z
[1-9] 1 or 2 ... or 8 or 9
\d digits [0-9]
\D non-digits [^0-9]
\s whitespace [ \t\n\r\f\v]
\S non-whitespace [^ \t\n\r\f\v]
\w alphanumeric [a-zA-Z0-9_]
\W non-alphanumeric [^a-zA-Z0-9_]
. any character
x* zero or more repetitions of x
x+ one or more repetitions of x
x? zero or one repetitions of x
{m} m repetitions
{m,n} m to n repetitions
{m,n} m to n repetitions
\\ \. \* backslash, period, asterisk
\b word boundary
^hello starts with hello
bye$ ends with bye
(...) capture group
(po|go) po or go
Solution 1¶
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Solution 2¶
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